![]() ![]() I found this as a guideline - Basic Diemaking Eugene Ostergaard R4T C=.5T R=Inside Bend Radius, T=Thickness of material, C=Location of neutral axis.Īnyway, back to the question - 1"X1/4" flat bar that has been rolled and has a diameter of 20". On tight bends it is closer to the inside of the bend. On a large bend radius in relation to the material thickness the neutral line is in the middle. So the thickness of the material has to be taken into account. So the length of the original bar is somewhere in the middle, called the neutral axis. When you bend something the outside will stretch and the inside will compress. I'll leave my somewhat redundant post below since it has a nice picture I stole on the web. Reading closely again I see that people have commented above on the same thing. But that difference of pi would only amount to 1/32" difference in the length of the metal to make a 20 inch circle. If the metal is one eighth thick, then you should add one eighth to the diameter before you multiply it by pi. ![]() My thought is if you roll it and it comes out almost an eighth inch in diameter too large, you can just grind a quarter inch off one end and your are good to go. The inside up against your die, is going to compress, the outside is going to expand, the actual size is somewhere in between. The reason is the thickness of the metal. You tend to need more length than just diameter times 3.14 Does this mean that in order to replicate that circle i would need to cut my flatbar to 62.8"? would that at least be very close? Does this math make sense? That math gives me a circumference of 62.8". Is this correct? I take the diameter of the existing rolled flatbar (20") and X that by 3.14 (pie). Lets say i have a magical break press that will only bend the straight flat bar once it senses the required flat length of the existing rolled flat bar. I am instructed to build one more of these starting from a straight piece of 1"X1/4" flat bar. So visually, this flat bar is in the shape of a circle now. Lets say there is a 1"X1/4" flat bar that has been rolled and has a diameter of 20". ![]()
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